45x^2-250x+125=0

Solution for 45x^2-250x+125=0 equation:

45x^2-250x+125=0

a = 45; b = -250; c = +125;
Δ = b2-4ac
Δ = -2502-4·45·125
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40000}=200$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-250)-200}{2*45}=\frac{50}{90}
=5/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-250)+200}{2*45}=\frac{450}{90}
=5
$